《Java Web應(yīng)用開(kāi)發(fā) 》期末試卷

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1、2011-2012學(xué)年第二學(xué)期考試卷(卷) 課程名稱:javawm應(yīng)用開(kāi)發(fā)占試方X:開(kāi)卷(〉閉卷( 題號(hào) 一 二 三 n 五 A 總分 沏人 考生注童事頊:1,本試卷共丄負(fù)?Wftfr試咎中經(jīng)舌存抉頁(yè)? 2、UIXMjK后.匕生不得將試卷、答超紙帶出歩場(chǎng). 一、選擇JS(毎小題1分,共20分) 得分 陽(yáng)#人 1. 表單中的數(shù)抵要捉交到的處理文件Itl表單的()用性描定. A. nethodB.nameC.actionD.以上都不對(duì) 2. 要運(yùn)行JSP程序?下列說(shuō)法不正確的是() A. 服務(wù)

2、話瑞需雯安裝Servlet?如"攻毗等. 5.客戶常爲(wèi)要安裝Servl躍客器?如Tce丈等. C. 服務(wù)話瑞需要安裝JDK. D. 客戶常爲(wèi)要安裝瀏覽器.如IE等. 3. 當(dāng)發(fā)布*小應(yīng)川程用時(shí).通常把Web用程用的目錄及文件放到Toncat 的()目錄下? A.workB.tempC.webappsD.conf 4. 下而有關(guān)HTTP協(xié)議的說(shuō)法不正確的是<> A.HTTP協(xié)議竝Web應(yīng)用所使用的上要協(xié)i義 B. HTTP協(xié)議是?種超文本傳輸協(xié)議(H:TertextTransferProtocol).是基于請(qǐng)求/響應(yīng)模式的 C. HTTP是無(wú)狀態(tài)協(xié)議 D. HTTP的請(qǐng)求和

3、響應(yīng)消息如果沒(méi)彳『發(fā)送并傳邊成功的話.HTTP可以保存已傳遞的佶息 5. 下而Servlet的描述WH吳的是(). A.—個(gè)Servlet就足Java中的一個(gè)類 B-Servlet位于盹b脳務(wù)器內(nèi)部的脳務(wù)器端的Java用程序 C. Servlet可以山客戶縮的瀏覽戀績(jī)斤執(zhí)行 D. 加較Servlet的leb眼務(wù)器必須包含支持Servle:的Java虛擬機(jī) 6. 下而不展干JSP描令的是:<) A.includeB.isportC.pageD.taglib 7. ()動(dòng)作用于轉(zhuǎn)向另一個(gè)頁(yè)而. A.nextB.forwardC.includeD.param S.在項(xiàng)目中已經(jīng)建立

4、了一個(gè)JavaSean.該類為:bean.Student?該beanH Hname.?性?則下if"標(biāo)簽用法正確的是:() A?

5、rtynane=*naneMproperty=*studenr*/> 9.下列選項(xiàng)中.(〉可以準(zhǔn)確地獲取請(qǐng)求頁(yè)而的一個(gè)文本框的輸入{文本樞的塔稱為naM). A.reQuest.getParanexer'nane) OAVAWEB開(kāi)反應(yīng)用??1M共6Jft B.reQuest.getParameterLname"> A.冏者在某些惆況下是等效的 C.request.getParameterValuesInaaei D.reQuest.getParameterValues(unase,f) B-“〔】"運(yùn)克符上妾用來(lái)訪何數(shù)組.列表或其他集合 10.使用response進(jìn)

6、行Jft定向時(shí).使用的方法是()? C.如果要?jiǎng)討B(tài)取(ft時(shí).兩者都可以實(shí)現(xiàn) A.getAttributeB.setContentljTe D.當(dāng)要存取的厲性名稱中包含一些特殊字符.如.或?等井非字每或數(shù)審 C.sendKedirectD.setAttribute 的符號(hào)?就一定要使用"[]“ 11.session対象中川于設(shè)定折定名字的厲性(ft?井且把它存佈在sessionXj 17.雯使用JSTL的核心標(biāo)簽庫(kù).需要在JSP文件的首部加入如下聲明語(yǔ)句 象中的方法是<>. () A.setAttributeB.getAttributeNames A.taglibpref

7、ix=*c* C.getValueD.setAttribute uri=* 12.A.application對(duì)欽中用<)方法可以獲Wapplication對(duì)Jl中的所有 B.taglibprefix=M 變fit名. uri=" A.getServerlnfoB.nextElenentsO C.taglibprefix=Mfmt" C.removeAttributeD.getRealPath uri=" 13.有關(guān)struts2的說(shuō)法不正確的是<) D.<%etaglibprefix=MsqIm A.Struts是一個(gè)用于簡(jiǎn)化XVCffi架(Framework)開(kāi)發(fā)的

8、WebW用権架 uri=" B.hlx/llStruts2不爲(wèi)耍進(jìn)行配Kt 18.以下()標(biāo)簽用干實(shí)現(xiàn)循環(huán)功能.類似勺Java譜句中的fs循環(huán). C.Struts2含有豐就的標(biāo)簽 A.B. D.Struts:采用fWebWork的核心技術(shù) B.

9、翌在頁(yè)而上ft{)iP,2-3=$(2-3}.則對(duì)應(yīng)的程序代碼應(yīng)為<〉? C.ftp:// A.2*3=\$(2*3} D.eO 5.2*3=3{2+3} 20.page折令用于定義JSP文件中的全簡(jiǎn)屈性?下列關(guān)干該描令用法的描述不 C.2+3=/$(2+3} 正確的是,() D.以上都不對(duì) A.<\epage?作用于整個(gè)JSP5(面. 16.下而有關(guān)EL中“.“和“[]“兩種存取運(yùn)第符的說(shuō)法不正確的是<) 葩2貝共貝 OAVAWEB圧廉應(yīng)用3 B. 可以在一個(gè)頁(yè)面中使用多個(gè)<%?page%>描令. C. 為增強(qiáng)程序的可或性?雄議將page%>|ft令放在J

10、SP文件的開(kāi)頭.但不是必須的. D. <3page指令中的屬性只能出現(xiàn)一次. 三、簡(jiǎn)答題,(毎小題6分.共30分) 得分 評(píng)農(nóng)人 1.TomcatHU務(wù)器的默認(rèn)常口是多少?怎樣修改tomcat的瑞L1 CJAVAWEB開(kāi)反應(yīng)用?第3貞共6貝 二.填空J(rèn)B(毎空2分,共20分) 得分 評(píng)總?cè)? 1. 在塢寫(xiě)Servlet時(shí)?需雯繼承類?在Servlet中聲明doGexO 和doPostO需要和類型的兩個(gè)參數(shù). 2. jsp主要內(nèi)51對(duì)象有:、exceptionwpageContext request、?.out、configspage

11、 3?便用useBean動(dòng)作標(biāo)記的時(shí)候scope屬性有4種選項(xiàng)?作用范囲由小到大足、、??其中足Hi當(dāng) 關(guān)閉瀏覽器的時(shí)候這個(gè)javabean夫效.是描當(dāng)關(guān)創(chuàng)眼務(wù)器的 時(shí)候這個(gè)javabean失效" 1.三種常用的動(dòng)態(tài)網(wǎng)頁(yè)技術(shù)足、、?簡(jiǎn)稱3P 技術(shù). 5.JSP利用JDEC極作數(shù)期庫(kù)的步驟:(1)加披雯動(dòng)程序?調(diào)用 將自動(dòng)加披更動(dòng)程序類:(2)健立連接.若連接7符出為: Stringurl=<,jdbc:mysql://localhost/*+dbNaM?*?user=,*-niserName?*&passvord=*mserPwd.其中dbName,userNane和userPv

12、d3個(gè)分別代農(nóng)、數(shù)無(wú)庫(kù)的和?<3)建立StareMent: (4)、執(zhí)trSQ1ifl句.其中.査詢數(shù)據(jù)庫(kù)里的表內(nèi)客是Statewnt接II使川方法:<5)關(guān)閉數(shù)摧庫(kù). 2.什么ftcookie?cookieW什么作用?. 3?簡(jiǎn)述JSP中動(dòng)態(tài)include與掙態(tài)include的區(qū)別? 4.簡(jiǎn)述農(nóng)單中POST和GET的區(qū)別. 5、MVC中的M、V、C各指的覽什么?請(qǐng)述其各自的作用? 四.編程■(毎小題15分.共50分) 得分 評(píng)卷人 1.編寫(xiě)一個(gè)御單的JavaBea

13、n?通過(guò)EL的存取運(yùn)算符訪何其屬性? 答案:文件userLogin.java定義了一個(gè)刖戶Man.包含姓名.密碼和電子郵件3個(gè)展性.其代碼如下, packagebean; publicclassuserLogin{ privateStringuserName; privat?String1L privatestringemai1; publicuserLoginO{ userName="李平"; password=”123"; email="lipingGsohu?com"; } publicvoidsetuserNamefStringuserName){ tMs?u

14、serName=userName; } publicStringgetuserNameO{ returnthis.userName; } publicvoidsetpasswordfStringpassword){ tMs?password=password; publicStringgetpasswrdO{ returnthis.password; } publicvoidsetemail(Stringemail){ this.?mail=email; } publicStringgetemail(){ returnthis?€皿彳1; } } 文件acce

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